x-8=(x^2+16)^1/2

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Solution for x-8=(x^2+16)^1/2 equation: 


x in (-oo:+oo)

x-8 = ((x^2+16)^1)/2 // - ((x^2+16)^1)/2

x-(((x^2+16)^1)/2)-8 = 0

x-((x^2+16)/2)-8 = 0

(-1*(x^2+16))/2+x-8 = 0

(-1*(x^2+16))/2+(2*x)/2+(-8*2)/2 = 0

2*x-1*(x^2+16)-8*2 = 0

2*x-x^2-16-16 = 0

2*x-x^2-32 = 0

2*x-x^2-32 = 0

2*x-x^2-32 = 0

DELTA = 2^2-(-32*(-1)*4)

DELTA = -124

DELTA < 0

1 = 0

1/2 = 0

1/2 = 0 // * 2

1 = 0

x belongs to the empty set

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